Computer Graphics MCQs with answers Page - 20

Here, you will find a collection of MCQ questions on Computer Graphics. Go through these questions to enhance your preparation for upcoming examinations and interviews.

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Q. Following are coordinates of clipping window : Lower Left Corner (20,20) and Upper Right Corner (200,200). A line has end coordinates as (5,50) and (15,150). The given line segment is ___________. Use Cohen – Sutherland Outcode Algorithm.

  • (A) completely visible
  • (B) partially visible
  • (C) completely invisible
  • (D) none of above

A

Admin • 833.24K Points
Coach

Q. Following are coordinates of clipping window : Lower Left Corner (20,20) and Upper Right Corner (200,200). A line has end coordinates as (0,10) and (250,15). The given line segment is ___________. Use Cohen – Sutherland Outcode Algorithm.

  • (A) completely visible
  • (B) partially visible
  • (C) completely invisible
  • (D) none of above

A

Admin • 833.24K Points
Coach

Q. A rectangular clipping window whose lower left corner is at (-3,1) and upper right corner is at (2,6). If line segment has end coordinates (-4,2) and (-1,7). What will the end coordinates of clipped line (use Cohen – Sutherland Outcode Algorithm)

  • (A) (-3, 11/3) and (-8/5, 6)
  • (B) (3/11, -3) and ( -5/8, 6)
  • (C) (-3, 3/11) and (-8/5,6)
  • (D) (-11/3, 3) and (-6, 8/5)

A

Admin • 833.24K Points
Coach

Q. In normalization transformation for window to viewport, window is lower left corner (1,1) and upper right corner at (3,5) to a view point with lower left corner at (0,0) and upper right corner at(1/2,1/2) .Scaling factor Sx =

  • (A) 0.25
  • (B) 0.125
  • (C) 4
  • (D) 0.5

A

Admin • 833.24K Points
Coach

Q. In normalization transformation for window to viewport, window is lower left corner (1,1) and upper right corner at (3,5) to a view point with lower left corner at (0,0) and upper right corner at(1/2,1/2) .Scaling factor Sy =

  • (A) 0.25
  • (B) 0.125
  • (C) 4
  • (D) 0.5

A

Admin • 833.24K Points
Coach

Q. In normalization transformation for window to viewport, window is lower left corner (1,1) and upper right corner at (3,5) to a view point with lower left corner at (0,0) and upper right corner at(1/2,1/2) .Scaling factors Sx =___ & Sy =___

  • (A) 0.25 & 0.125
  • (B) 0.125 & 0.25
  • (C) 4 & 8
  • (D) 0.5 & 1

A

Admin • 833.24K Points
Coach

Q. In normalization transformation for window to viewport, window is lower left corner (2,2) and upper right corner at (6,10) to a view point with lower left corner at (0,0) and upper right corner at(1, 1) .Scaling factor Sx =___

  • (A) 0.25
  • (B) 0.125
  • (C) 0.5
  • (D) 4

A

Admin • 833.24K Points
Coach

Q. In normalization transformation for window to viewport, window is lower left corner (2,2) and upper right corner at (6,10) to a view point with lower left corner at (0,0) and upper right corner at(1, 1) .Scaling factor Sy=___

  • (A) 0.25
  • (B) 0.125
  • (C) 0.5
  • (D) 4

A

Admin • 833.24K Points
Coach

Q. In normalization transformation for window to viewport, window is lower left corner (2,2) and upper right corner at (6,10) to a view point with lower left corner at (0,0) and upper right corner at(1, 1) .Scaling factors Sx =___ & Sy= ___

  • (A) 0.25 & 0.5
  • (B) 0.25 & 0.125
  • (C) 0.5 & 0.25
  • (D) 0.125 & 0.25

A

Admin • 833.24K Points
Coach

Q. In viewing from a window in world coordinates with x extent 3 to 12 & y extent 2 to 10 onto a viewport with x extent ¼ to 3/4and y extent 0 to ½ in normalized device space .Scaling factors Sx=

  • (A) (1/18)
  • (B) (1/16)
  • (C) 18
  • (D) 16

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