A
Q. What is the output of the following code :
Code:print 9//2
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print 9//2
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i = 0 while i < 3: print i print i+1
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def myfunc(a): a = a + 2 a = a * 2 return a print myfunc(2)
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i = 0
while i < 5:
print(i)
i += 1
if i == 3:
break
else:
print(0)
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def f(value, values):
v = 1
values[0] = 44
t = 3
v = [1, 2, 3]
f(t, v)
print(t, v[0])
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