A

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Q. If the critical field in a Gunn diode oscillator is 3.2 KV/cm and effective length is 20 microns, then the critical voltage is:

  • (A) 3.2 v
  • (B) 6.4 v
  • (C) 2.4 v
  • (D) 6.5 v

Explanation by: Admin

critical voltage of a gunn diode oscillator is given by the expression lec where l is the effective length and ec is the critical field. substituting the given values in the above equation, critical voltage is 6.4 volts.

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