Learn JavaScript MCQ Questions with answers and solutions.

A

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Q. Which of the following uses a lot of CPU cycles?

(A) GUI
(B) Statically generated graphics
(C) Dynamically generated graphics
(D) All of the mentioned

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Q. Consider the following code snippet :
var scope = "global scope";
function checkscope() {
var scope = "local scope";
function f()
{
return scope;
}
return f;
What is the function of the above code snippet?

(A) Returns value null
(B) Returns exception
(C) Returns the value in scope
(D) None of the mentioned

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Q. What is the fundamental rule of lexical scoping?

(A) Functions are declared in the scope
(B) Functions are executed using scope chain
(C) All of the mentioned
(D) None of the mentioned

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Q. Consider the following code snippet :
var tensquared = (function(x) {return x*x;}(10));
Will the above code work ?

(A) Yes, perfectly
(B) Error
(C) Exception will be thrown
(D) Memory leak

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Q. Consider the following code snippet :
var string2Num=parseInt("123xyz");
The result for the above code snippet would be :

(A) 123
(B) 123xyz
(C) Exception
(D) NaN

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Q. If you have a function f and an object o, you can define a method named m of o with

(A) o.m=m.f;
(B) o.m=f;
(C) o=f.m;
(D) o=f;

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Q. For the below mentioned code snippet:
var o = new Object();
The equivalent statement is:

(A) var o = Object();
(B) var o;
(C) var o= new Object;
(D) Object o=new Object();

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Q. What is the difference between the two lines given below ?
!!(obj1 && obj2);
(obj1 && obj2);

(A) Both the lines result in a boolean value “True”
(B) Both the lines result in a boolean value “False”
(C) Both the lines checks just for the existence of the object alone
(D) The first line results in a real boolean value whereas the second line merely checks for the existence of the objects

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Q. Consider the following code snippet :
var c = counter(), d = counter();
c.count()
d.count()
c.reset()
c.count()
d.count()
The state stored in d is :

(A) 1
(B) 0
(C) Null
(D) Undefined

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Q. Consider the following code snippet :
var c = counter(), d = counter();
function constfuncs()
{
var funcs = [];
for(var i = 0; i < 10; i++)
funcs[i] = function() { return i; };
return funcs;
}
var funcs = constfuncs();
funcs[5]()
What does the last statement return ?

(A) 9
(B) 0
(C) 10
(D) None of the mentioned

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JavaScript MCQs with answers Page - 65

Q. Which of the following uses a lot of CPU cycles?

Q. Consider the following code snippet :
var scope = "global scope";
function checkscope() {
var scope = "local scope";
function f()
{
return scope;
}
return f;
What is the function of the above code snippet?

Q. What is the fundamental rule of lexical scoping?

Q. Consider the following code snippet :
var tensquared = (function(x) {return x*x;}(10));
Will the above code work ?

Q. Consider the following code snippet :
var string2Num=parseInt("123xyz");
The result for the above code snippet would be :

Q. If you have a function f and an object o, you can define a method named m of o with

Q. For the below mentioned code snippet:
var o = new Object();
The equivalent statement is:

Q. What is the difference between the two lines given below ?
!!(obj1 && obj2);
(obj1 && obj2);

Q. Consider the following code snippet :
var c = counter(), d = counter();
c.count()
d.count()
c.reset()
c.count()
d.count()
The state stored in d is :

Q. Consider the following code snippet :
var c = counter(), d = counter();
function constfuncs()
{
var funcs = [];
for(var i = 0; i < 10; i++)
funcs[i] = function() { return i; };
return funcs;
}
var funcs = constfuncs();
funcs[5]()
What does the last statement return ?

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JavaScript MCQs with answers Page - 65

Q. Which of the following uses a lot of CPU cycles?

Q. Consider the following code snippet : var scope = "global scope"; function checkscope() { var scope = "local scope"; function f() { return scope; } return f; What is the function of the above code snippet?

Q. What is the fundamental rule of lexical scoping?

Q. Consider the following code snippet : var tensquared = (function(x) {return x*x;}(10)); Will the above code work ?

Q. Consider the following code snippet : var string2Num=parseInt("123xyz"); The result for the above code snippet would be :

Q. If you have a function f and an object o, you can define a method named m of o with

Q. For the below mentioned code snippet: var o = new Object(); The equivalent statement is:

Q. What is the difference between the two lines given below ? !!(obj1 && obj2); (obj1 && obj2);

Q. Consider the following code snippet : var c = counter(), d = counter(); c.count() d.count() c.reset() c.count() d.count() The state stored in d is :

Q. Consider the following code snippet : var c = counter(), d = counter(); function constfuncs() { var funcs = []; for(var i = 0; i < 10; i++) funcs[i] = function() { return i; }; return funcs; } var funcs = constfuncs(); funcs[5]() What does the last statement return ?

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Q. Consider the following code snippet :
var scope = "global scope";
function checkscope() {
var scope = "local scope";
function f()
{
return scope;
}
return f;
What is the function of the above code snippet?

Q. Consider the following code snippet :
var tensquared = (function(x) {return x*x;}(10));
Will the above code work ?

Q. Consider the following code snippet :
var string2Num=parseInt("123xyz");
The result for the above code snippet would be :

Q. For the below mentioned code snippet:
var o = new Object();
The equivalent statement is:

Q. What is the difference between the two lines given below ?
!!(obj1 && obj2);
(obj1 && obj2);

Q. Consider the following code snippet :
var c = counter(), d = counter();
c.count()
d.count()
c.reset()
c.count()
d.count()
The state stored in d is :

Q. Consider the following code snippet :
var c = counter(), d = counter();
function constfuncs()
{
var funcs = [];
for(var i = 0; i < 10; i++)
funcs[i] = function() { return i; };
return funcs;
}
var funcs = constfuncs();
funcs[5]()
What does the last statement return ?