Dynamics of Machinary MCQs with answers Page - 5

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Q. Let the centrifugal force in kN be 25 and the radius of rotation be 20 cm and the rotation speed be 50 rad/s, then calculate the mass defect in Kg.

  • (A) 50
  • (B) 25
  • (C) 50000
  • (D) 25000

A

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Q. In a multicylinder inline engine, each imaginary secondary crank with a mass attached to the crankpin is inclined to the line of stroke at which angle?

  • (A) Twice the angle of crank
  • (B) Half the angle of crank
  • (C) Thrice the angle of crank
  • (D) Four times the angle of crank

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Q. In order to achieve stability, the sum of secondary forces and secondary couples must be ------- and their respective polygons must be …......

  • (A) Zero, Closed
  • (B) one, Open
  • (C) Zero, open
  • (D) one, closed

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Q. For the secondary balancing of the engine, which of the condition is necessary?

  • (A) Secondary force polygon must be close
  • (B) Secondary force polygon must be open
  • (C) Primary force polygon must be close
  • (D) Primary force polygon must be open

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Q. The numerical values of the secondary forces and secondary couples couples may be obtained by considering the ___________

  • (A) Revolving mass
  • (B) Reciprocating mass
  • (C) Translating mass
  • (D) Rotating mass

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Q. Which of the following is the correct expression for secondary force?

  • (A) m?^2r.cos2θ/n
  • (B) m ?^2r.sin2θ/n
  • (C) m?^2r.tan2θ/n
  • (D) m?^2r.cosθ/n

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Q. A V-twin engine has the cylinder axes at 90 degrees and the connecting rods operate a common crank. The reciprocating mass per cylinder is 23 kg and the crank radius is 7.5 cm. The length of the connecting rod is 0.3 m. If the engine is rotating at the speed is 500 r.p.m. What is the value of maximum resultant secondary force in Newtons?

  • (A) 7172
  • (B) 1672
  • (C) 1122
  • (D) 1272

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Q. A V-twin engine has the cylinder axes at 90 degrees and the connecting rods operate a common crank. The reciprocating mass per cylinder is 34.5 kg and the crank radius is 7.5 cm. The length of the connecting rod is 0.3 m. If the engine is rotating at the speed is 500 r.p.m. What is the value of maximum resultant secondary force in kN?

  • (A) 2.238
  • (B) 2.508
  • (C) 2.754
  • (D) 2.908

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Q. From the given data, find the balancing mass in Kg if r=0.2m required in the same plane.Masses = 200kg, 300kg, 240 kg, 260Kg, corresponding radii = 0.2m, 0.15m, 0.25m and 0.3m.Angles between consecutive masses = 45, 75 and 135 degrees.

  • (A) 116
  • (B) 58
  • (C) 232
  • (D) 140

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Q. Let the disturbing mass be 200 kg and the radius of rotation be 20 cm and the rotation speed be 50 rad/s, then calculate the centripetal force in kN.

  • (A) -50
  • (B) -25
  • (C) -100
  • (D) -2500

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