A

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Q. The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:

  • (A) 74
  • (B) 94
  • (C) 184
  • (D) 364
  • Correct Answer - Option(D)
  • Views: 14
  • Filed under category Math
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Explanation by: Admin
L.C.M. of 6, 9, 15 and 18 is 90
Let required number be 90k + 4, which is multiple of 7
Least value of k for which (90k + 4) is divisible by 7 is k = 4
So Required number = (90 x 4) + 4 = 364

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