Let the numbers 13a and 13b
Then, 13a x 13b = 2028
⇒ ab = 12
Now, the co-primes with product 12 are (1, 12) and (3, 4)
[Note: Two integers a and b are said to be co-prime or relatively prime if they have no common positive factor other than 1 or, equivalently, if their greatest common divisor is 1 ]
So, the required numbers are (13 x 1, 13 x 12) and (13 x 3, 13 x 4)
Clearly, there are 2 such pairs.
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