What does the & operator do when used with a proc in Ruby?

Question

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Converts the proc into a block so it can be passed to a method that expects a block parameter

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Invokes the proc with the given arguments

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Converts the proc into a lambda so it can be passed to a method that expects a lambda parameter

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Converts the proc into a method so it can be called directly

Q. What does the & operator do when used with a proc in Ruby?