A

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Q. What is the output of the given code?
for counter in 1..5
case counter
when 0 .. 2
puts counter
puts "baby"
when 3 .. 6
puts counter
puts "little child"
when 7 .. 12
puts counter
puts "child"
else
puts counter
puts "adult"
end
end

  • (A) adult 1..5
  • (B) b alphabet b
  • (C) 1 baby 2 baby 3 little child 4 little child 5 little child
  • (D) adult
  • Correct Answer - Option(C)
  • Views: 6
  • Filed under category Ruby
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