A
Q. What will be the final values of i and j in the following C code?
Code:
#include <stdio.h>
int x = 0;
int main()
{
int i = (f() + g()) | g(); //bitwise or
int j = g() | (f() + g()); //bitwise or
}
int f()
{
if (x == 0)
return x + 1;
else
return x - 1;
}
int g()
{
return x++;
}
int x = 0;
int main()
{
int i = (f() + g()) | g(); //bitwise or
int j = g() | (f() + g()); //bitwise or
}
int f()
{
if (x == 0)
return x + 1;
else
return x - 1;
}
int g()
{
return x++;
}
- Correct Answer - Option(C)
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