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Q. What is the result of the following code snippet?

try {
throw new NullPointerException();
} catch (ArithmeticException e) {
System.out.println("Arithmetic Exception!");
} catch (NullPointerException e) {
System.out.println("NullPointerException!");
}

(A) NullPointerException!
(B) Compilation error
(C) Runtime exception
(D) Arithmetic Exception!

Correct Answer - Option(A)
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Filed under category Java
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Explanation by: Admin

In the given code snippet, a NullPointerException is explicitly thrown within the try block. When an exception is thrown, the Java runtime looks for a catch block that matches the type of the thrown exception.

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Q. What is the result of the following code snippet? try { throw new NullPointerException(); } catch (ArithmeticException e) { System.out.println("Arithmetic Exception!"); } catch (NullPointerException e) { System.out.println("NullPointerException!"); }

Explanation by: Admin

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Q. What is the result of the following code snippet?

try {
throw new NullPointerException();
} catch (ArithmeticException e) {
System.out.println("Arithmetic Exception!");
} catch (NullPointerException e) {
System.out.println("NullPointerException!");
}