A

Admin • 828.03K Points
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Q. What will be printed after executing following program code?
class Base{
int value = 0;
Base(){
addValue();
}
void addValue(){
value += 10;
}
int getValue(){
return value;
}
}
class Derived extends Base{
Derived(){
addValue();
}
void addValue(){
value += 20;
}
}
public class Test{
public static void main(String[] args){
Base b = new Derived();
System.out.println(b.getValue());
}
}

  • (A) 30
  • (B) 10
  • (C) 40
  • (D) 40 D. 20
  • Correct Answer - Option(C)
  • Views: 23
  • Filed under category Java
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Explanation by: Admin
When object of new derived is called, the flow goes to Derived() first, by default super(); is present in Derived() as the first statement, so the flow now goes to Base. Here value is initialised to 0 and then addValue() is called. The addValue has been overridden in Derived() hence The Base's addValue() will perform value+20(0+20) .After this control flows back to Derived()'s addValue() where again value+20 is done (20+20). Hence Answer is 40

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