What happens if the following program is compiled and executed?
interface MyInterface{
void display();
}

interface MySubInterface extends MyInterface{
void display();
}

public class Test implements MySubInterface{
public void display(){
System.out.print("Welcome to Examveda.");
}
public static void main(String args[]){
Test t = new Test();
t.display();
}
}

Question

What happens if the following program is compiled and executed?
interface MyInterface{
      void display();
}

interface MySubInterface extends MyInterface{
      void display();
}

public class Test implements MySubInterface{
      public void display(){
            System.out.print("Welcome to Examveda.");
      }
      public static void main(String args[]){
            Test t = new Test();
     t.display();
      }
}

Admin · Accepted Answer

The code will compile and execute successfully showing the output Welcome to Examveda.

Admin · Answer

The code will lead to a compilation error as declaration of the display method has been provided in two interface.

Admin · Answer

The code will lead to a compilation error due to public modifier while declaring the display method.

Admin · Answer

The code will compile and execute successfully showing the output Welcome to Examveda.
D.
The code will lead to a compilation error as the display method is not declared as abstract.

Explanation by: Admin

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