Determine output:
class MyClass{
int i;
int j;

public MyClass(int i, int j){
this.i = i;
this.j = j;
}

public void call(){
System.out.print("One");
}
}

public class Test{
public static void main(String args[]){
MyClass m = new MyClass(); //line 1
m.call(); //line 2
}
}

Question

Determine output:
class MyClass{
 int i;
 int j;

public MyClass(int i, int j){
  this.i = i;
  this.j = j;
 }

public void call(){
  System.out.print("One");
 }
}

public class Test{
 public static void main(String args[]){
  MyClass m = new MyClass(); //line 1
  m.call(); //line 2
 }
}

Admin · Accepted Answer

Compilation fails due to an error on line 1

Admin · Answer

One

Admin · Answer

Compilation fails due to an error on line 2

Admin · Answer

Compilation succeed but no output.

Q. Determine output:
class MyClass{
int i;
int j;

public MyClass(int i, int j){
this.i = i;
this.j = j;
}

public void call(){
System.out.print("One");
}
}

public class Test{
public static void main(String args[]){
MyClass m = new MyClass(); //line 1
m.call(); //line 2
}
}