What is the output for the below code?
public class Test{
int _$;
int $7;
int do;

public static void main(String argv[]){
Test test = new Test();
test.$7=7;
test.do=9;
System.out.println(test.$7);
System.out.println(test.do);
System.out.println(test._$);
}
}

Question

What is the output for the below code?
public class Test{
      int _$;
      int $7;
      int do;

public static void main(String argv[]){
            Test test = new Test();
            test.$7=7;
            test.do=9;
            System.out.println(test.$7);
            System.out.println(test.do);
            System.out.println(test._$);
      }
}

Admin · Accepted Answer

Compile error - $7 is not valid identifier.
D.
Compile error - do is not valid identifier.

Admin · Answer

7 9 0

Admin · Answer

7 0 0

Admin · Answer

Compile error - $7 is not valid identifier.

Q. What is the output for the below code?
public class Test{
int _$;
int $7;
int do;

public static void main(String argv[]){
Test test = new Test();
test.$7=7;
test.do=9;
System.out.println(test.$7);
System.out.println(test.do);
System.out.println(test._$);
}
}

Explanation by: Admin

Discusssion

Q. What is the output for the below code? public class Test{ int _$; int $7; int do; public static void main(String argv[]){ Test test = new Test(); test.$7=7; test.do=9; System.out.println(test.$7); System.out.println(test.do); System.out.println(test._$); } }

Explanation by: Admin

Discusssion

Q. What is the output for the below code?
public class Test{
int _$;
int $7;
int do;

public static void main(String argv[]){
Test test = new Test();
test.$7=7;
test.do=9;
System.out.println(test.$7);
System.out.println(test.do);
System.out.println(test._$);
}
}