G

Gourav • 2.17K Points
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Q. If sec θ = 13/5, then tan θ = ?

  • (A) 5/12
  • (B) 12/5
  • (C) 13/12
  • (D) 12/13

Explanation by: Gourav

Using sec²θ = 1 + tan²θ, tan²θ = 169/25 − 1 = 144/25.

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