A

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Q. The time taken by all-to- all broadcast on a mesh is .

  • (A) t= (ts + twm)(p-1)
  • (B) t= ts logp + twm(p-1)
  • (C) t= 2ts(√p – 1) - twm(p-1)
  • (D) t= 2ts(√p – 1) + twm(p-1)

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