A

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Q. An antenna has a field pattern of E (θ) = cos2 θ, θ varies between 0 and 900. Half power beam width of the antenna is:

  • (A) 330
  • (B) 660
  • (C) 12000
  • (D) none of the mentioned

Explanation by: Admin

half power beam width of the antenna is obtained by equating the field pattern of the antenna to 0.707 (half power point) and finding θ. 2θ gives the value of beam width. solving the given problem in the same flow, half power beam width of the antenna is 660.

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